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Continued fraction for sqrt(259).
1

%I #16 Dec 27 2023 01:13:11

%S 16,10,1,2,3,4,3,2,1,10,32,10,1,2,3,4,3,2,1,10,32,10,1,2,3,4,3,2,1,10,

%T 32,10,1,2,3,4,3,2,1,10,32,10,1,2,3,4,3,2,1,10,32,10,1,2,3,4,3,2,1,10,

%U 32,10,1,2,3,4,3,2,1,10,32,10,1,2,3,4,3,2,1,10,32

%N Continued fraction for sqrt(259).

%H <a href="/index/Con#confC">Index entries for continued fractions for constants</a>

%H <a href="/index/Rec#order_10">Index entries for linear recurrences with constant coefficients</a>, signature (0, 0, 0, 0, 0, 0, 0, 0, 0, 1).

%p with(numtheory): Digits := 300: convert(evalf(sqrt(259)),confrac);

%t ContinuedFraction[Sqrt[259],120] (* or *) PadRight[{16},120,{32,10,1,2,3,4,3,2,1,10}] (* _Harvey P. Dale_, Jan 02 2018 *)

%K nonn,cofr,easy

%O 0,1

%A _N. J. A. Sloane_.