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Continued fraction for sqrt(253).
0

%I #11 Sep 23 2018 19:36:19

%S 15,1,9,1,1,1,2,1,7,4,2,2,2,4,7,1,2,1,1,1,9,1,30,1,9,1,1,1,2,1,7,4,2,

%T 2,2,4,7,1,2,1,1,1,9,1,30,1,9,1,1,1,2,1,7,4,2,2,2,4,7,1,2,1,1,1,9,1,

%U 30,1,9,1,1,1,2,1,7,4,2,2,2,4,7,1,2,1,1,1,9,1,30,1,9

%N Continued fraction for sqrt(253).

%H <a href="/index/Con#confC">Index entries for continued fractions for constants</a>

%H <a href="/index/Rec#order_22">Index entries for linear recurrences with constant coefficients</a>, signature (0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1).

%p with(numtheory): Digits := 300: convert(evalf(sqrt(253)),confrac);

%t ContinuedFraction[Sqrt[253],120] (* or *) PadRight[{15},120,{30,1,9,1,1,1,2,1,7,4,2,2,2,4,7,1,2,1,1,1,9,1}] (* _Harvey P. Dale_, Sep 23 2018 *)

%K nonn,cofr,easy

%O 0,1

%A _N. J. A. Sloane_.