%I #11 Sep 23 2018 19:36:19
%S 15,1,9,1,1,1,2,1,7,4,2,2,2,4,7,1,2,1,1,1,9,1,30,1,9,1,1,1,2,1,7,4,2,
%T 2,2,4,7,1,2,1,1,1,9,1,30,1,9,1,1,1,2,1,7,4,2,2,2,4,7,1,2,1,1,1,9,1,
%U 30,1,9,1,1,1,2,1,7,4,2,2,2,4,7,1,2,1,1,1,9,1,30,1,9
%N Continued fraction for sqrt(253).
%H <a href="/index/Con#confC">Index entries for continued fractions for constants</a>
%H <a href="/index/Rec#order_22">Index entries for linear recurrences with constant coefficients</a>, signature (0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1).
%p with(numtheory): Digits := 300: convert(evalf(sqrt(253)),confrac);
%t ContinuedFraction[Sqrt[253],120] (* or *) PadRight[{15},120,{30,1,9,1,1,1,2,1,7,4,2,2,2,4,7,1,2,1,1,1,9,1}] (* _Harvey P. Dale_, Sep 23 2018 *)
%K nonn,cofr,easy
%O 0,1
%A _N. J. A. Sloane_.