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A039942 Number of points needed to display n on the LCD (liquid-crystal display) of a TI-83 calculator. 1

%I #34 Sep 19 2020 22:58:57

%S 19,10,14,14,14,17,15,11,17,15,29,20,24,24,24,27,25,21,27,25,33,24,28,

%T 28,28,31,29,25,31,29,33,24,28,28,28,31,29,25,31,29,33,24,28,28,28,31,

%U 29,25,31,29,36,27,31,31,31,34,32,28,34,32,34,25,29,29,29,32,30,26,32

%N Number of points needed to display n on the LCD (liquid-crystal display) of a TI-83 calculator.

%C a(15) = a(1) + a(5);

%C a(29) = a(2) + a(9) = 29 is the unique term such that a(n) = n.

%C a(10*n+u) = a(n) + a(u) where n >= 1 is a number and u a digit. - _Jean-Marc Rebert_, Aug 02 2015

%H Indranil Ghosh, <a href="/A039942/b039942.txt">Table of n, a(n) for n = 0..50000</a>

%H <a href="/index/Ca#calculatordisplay">Index entries for sequences related to calculator display</a>

%e _XXX____X_

%e X___X__XX_

%e X__XX___X_

%e X_X_X___X_

%e XX__X___X_

%e X___X___X_

%e _XXX___XXX

%t Table[DigitCount[n].{10, 14, 14, 14, 17, 15, 11, 17, 15, 19}, {n, 0, 68}] (* _Michael De Vlieger_, Feb 02 2017 *)

%o (PARI) a(n)={if(n==0,return(19)); my(p=[19, 10, 14, 14, 14, 17, 15, 11, 17, 15], d=digits(n), s=0); for(j=1,#d,s+=p[d[j]+1]); s;} \\ _Joerg Arndt_, Aug 02 2015

%o (Python)

%o def A039942(n):

%o ....s=0

%o ....for i in str(n):

%o ........s+=[19,10,14,14,14,17,15,11,17,15][int(i)]

%o ....return s # _Indranil Ghosh_, Feb 02 2017

%K easy,nonn,base

%O 0,1

%A _Jean-Marc Rebert_

%E More terms from _David Wasserman_, Feb 04 2002

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Last modified April 25 07:07 EDT 2024. Contains 371964 sequences. (Running on oeis4.)