OFFSET
1,1
COMMENTS
Contains (k+5(2j+1))^3-k^3 for any integers k,j>=0. - M. F. Hasler, May 31, 2007
FORMULA
A number is in this sequence iff it is of the form (k+10j-5)^3-k^3, where k,j are any positive integers, since (k+d)^3 - k^3 = d(3(k+d/2)^2+d^2/4) == 5 (mod 10) iff d is odd and d == 0 (mod 5) (cf. A038853) - M. F. Hasler, Jun 07 2007
PROG
(PARI) A038860(Nmax=20000, a=[]) = { local(t, j5); forstep( j=1, Nmax^(1/3)/5, 2, j5=5*j; for(k=1, sqrt((Nmax/j5-j5^2-3*j5)/3), if(Nmax<t=(k+j5)^3-k^3, break); a=concat(a, t))); vecsort(a) } \\ M. F. Hasler, Jun 07 2007
CROSSREFS
KEYWORD
nonn,base
AUTHOR
EXTENSIONS
Corrected by M. F. Hasler, Jun 07 2007
STATUS
approved