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Table of n, a(n) for n=1..64.
a(15)=[ 15/1 ]+[ 15/2 ]+[ 15/3 ]+[ 15/5 ]+[ 15/8 ]+[ 15/13 ]+[ 15/21 ]+...=32.
with(combinat): for n from 1 to 200 do printf(`%d, `, sum(floor(n/fibonacci(k)), k=2..15)) od:
Sequence in context: A131628 A079091 A191749 * A246405 A190328 A248106
Adjacent sequences: A038660 A038661 A038662 * A038664 A038665 A038666
Antreas P. Hatzipolakis (xpolakis(AT)hol.gr)
More terms from Simon Plouffe, who points out that the first differences give A005086
More terms from James A. Sellers, Feb 19 2001