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A038179 Result of second stage of sieve of Eratosthenes (after eliminating multiples of 2 and 3). 17
2, 3, 5, 7, 11, 13, 17, 19, 23, 25, 29, 31, 35, 37, 41, 43, 47, 49, 53, 55, 59, 61, 65, 67, 71, 73, 77, 79, 83, 85, 89, 91, 95, 97, 101, 103, 107, 109, 113, 115, 119, 121, 125, 127, 131, 133, 137, 139, 143, 145, 149, 151 (list; graph; refs; listen; history; text; internal format)
OFFSET
1,1
COMMENTS
2, 3 and numbers of the form 6m +- 1.
Apart from first two terms, same as A007310.
Terms of this sequence (starting from the third term) are equal to the result of the expression sqrt(4!*(k+1) + 1) - but only when this expression yields integral values (that is when the parameter k takes values, which are terms of A144065). - Alexander R. Povolotsky, Sep 09 2008
REFERENCES
Fred S. Roberts, Applied Combinatorics, Prentice-Hall, 1984, p. 256.
LINKS
Ahmed Hamdy A. Diab, Sequence eliminating law (SEL) and the interval formulas of prime numbers, arXiv:2012.03052 [math.NT], 2020.
H. B. Meyer, Eratosthenes' sieve.
FORMULA
O.g.f.: x*(2 + x + x^3 + 2x^4)/((1+x)*(1-x)^2). - R. J. Mathar, May 23 2008
a(n) = (1/9)*(4*n^3 + 3*n^2 + 1 - Kronecker(-3,n+1)). - Ralf Stephan, Jun 01 2014
From Mikk Heidemaa, Oct 28 2017: (Start)
a(n) = floor((41/21 - (3 mod n))^(-3*n+5)) + 3*n - 4 (n > 0).
a(n+1) = 3*n - ((n mod 2)+1) mod n (n > 0). (End)
a(n+2) = 2*floor((3*n+1)/2) + 1 for n>=1; see (17) in Diab link. - Michel Marcus, Dec 14 2020
Sum_{n>=1} (-1)^(n+1)/a(n) = (7-sqrt(3)*Pi)/6. - Amiram Eldar, Sep 22 2022
MATHEMATICA
max = 200; Complement[Range[2, max], 2Range[2, Ceiling[max/2]], 6Range[2, Ceiling[max/6]] + 3] (* Alonso del Arte, May 16 2014 *)
Prepend[Table[3*n - Mod[ Mod[n, 2] + 1, n], {n, 1, 999}], 2] (* Mikk Heidemaa, Nov 02 2017 *)
CROSSREFS
Sequence in context: A048380 A048382 A352584 * A192489 A161578 A261271
KEYWORD
nonn,easy
AUTHOR
N. J. A. Sloane, Dec 11 1999
EXTENSIONS
Name edited by Michel Marcus, Dec 14 2020
STATUS
approved

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Last modified April 25 06:35 EDT 2024. Contains 371964 sequences. (Running on oeis4.)