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Base 8 digits are, in order, the first n terms of the periodic sequence with initial period 3,2,0.
1

%I #15 Jun 13 2015 00:49:17

%S 3,26,208,1667,13338,106704,853635,6829082,54632656,437061251,

%T 3496490010,27971920080,223775360643,1790202885146,14321623081168,

%U 114572984649347,916583877194778,7332671017558224,58661368140465795,469290945123726362

%N Base 8 digits are, in order, the first n terms of the periodic sequence with initial period 3,2,0.

%H Colin Barker, <a href="/A037671/b037671.txt">Table of n, a(n) for n = 1..1000</a>

%H <a href="/index/Rec#order_04">Index entries for linear recurrences with constant coefficients</a>, signature (8,0,1,-8).

%F a(n) = 8*a(n-1)+a(n-3)-8*a(n-4). - _Colin Barker_, Dec 07 2014

%F G.f.: x*(2*x+3) / ((x-1)*(8*x-1)*(x^2+x+1)). - _Colin Barker_, Dec 07 2014

%o (PARI) Vec(x*(2*x+3)/((x-1)*(8*x-1)*(x^2+x+1)) + O(x^100)) \\ _Colin Barker_, Dec 08 2014

%K nonn,base,easy

%O 1,1

%A _Clark Kimberling_

%E More terms from _Colin Barker_, Dec 08 2014