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Replace 2n+1 with concatenation of its divisors.
0

%I #7 Mar 31 2017 22:41:26

%S 1,13,15,17,139,111,113,13515,117,119,13721,123,1525,13927,129,131,

%T 131133,15735,137,131339,141,143,13591545,147,1749,131751,153,151155,

%U 131957,159,161,13792163,151365,167,132369,171,173,135152575,171177

%N Replace 2n+1 with concatenation of its divisors.

%e Divisors of 15 are 1,3,5,15, so a(7)=13515

%K nonn,base,easy

%O 0,2

%A _N. J. A. Sloane_

%E More terms from _Erich Friedman_