%I #7 Mar 31 2017 22:41:26
%S 1,13,15,17,139,111,113,13515,117,119,13721,123,1525,13927,129,131,
%T 131133,15735,137,131339,141,143,13591545,147,1749,131751,153,151155,
%U 131957,159,161,13792163,151365,167,132369,171,173,135152575,171177
%N Replace 2n+1 with concatenation of its divisors.
%e Divisors of 15 are 1,3,5,15, so a(7)=13515
%K nonn,base,easy
%O 0,2
%A _N. J. A. Sloane_
%E More terms from _Erich Friedman_