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A037229 n such that pi(n) >= phi(n). 2

%I #27 Dec 12 2018 07:00:50

%S 2,3,4,6,8,10,12,14,18,20,24,30,42,60,90

%N n such that pi(n) >= phi(n).

%C It is known (see references) that, for n>15, phi(n)>n/(e^c*log(log(n))+3) and pi(n)<1.25506*n/log(n), where c is the Euler constant. Therefore, there are no terms, at least, for n satisfying the inequality: log(n)/(e^c*log(log(n))+3)>1.25506... So, for, e.g., n>=5500, there are no terms. Besides, by the direct verification, we find that interval (90,5500) contains no terms as well. - _Vladimir Shevelev_, Aug 27 2011

%D N. E. Bach, J. Shallit, Algorithmic Number Theory, MIT Press, 233 (1996). ISBN 0-262-02405-5 (Theorem 8.8.7)

%H J. Barkley Rosser and Lowell Schoenfeld, <a href="http://projecteuclid.org/euclid.ijm/1255631807">Approximate formulas for some functions of prime numbers</a>, Ill. Journ. Math. 6 (1962) 64-94.

%Y Cf. A000010, A000720, A037171, A037228, A073464.

%K nonn,fini,full

%O 0,1

%A _David W. Wilson_

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