
COMMENTS

Suggestion from Rickey Bowers Jr, (math(AT)bitRAKE.com), May 18 2006:
a(0) = 5,
a(1) = 2 * prime(5),
a(2) = (prime(5))^2,
a(3) = 2^4 * prime(prime(5)),
a(4) = (prime(prime(5)))^(2^4),
...
a(2n1) = (2^(n^2)) * prime^n(a(0)),
a(2n) = prime^n(a(0))^(2^(n^2)).
