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A036217
Expansion of 1/(1-3*x)^5; 5-fold convolution of A000244 (powers of 3).
16
1, 15, 135, 945, 5670, 30618, 153090, 721710, 3247695, 14073345, 59108049, 241805655, 967222620, 3794488740, 14635885140, 55616363532, 208561363245, 772903875555, 2833980877035, 10291825290285, 37050571045026
OFFSET
0,2
COMMENTS
With a different offset, number of n-permutations (n=5) of 4 objects: u, v, z, x with repetition allowed, containing exactly four (4) u's. Example: a(1)=15 because we have uuuuv uuuvu uuvuu uvuuu vuuuu uuuuz uuuzu uuzuu uzuuu zuuuu uuuux uuuxu uuxuu uxuuu xuuuu. - Zerinvary Lajos, Jun 12 2008
FORMULA
a(n) = 3^n*binomial(n+4, 4) = 3^n*A000332(n+4).
a(n) = A027465(n+5, 5).
G.f.: 1/(1-3*x)^5.
E.g.f.: (1/8)*(8 +96*x +216*x^2 +144*x^3 +27*x^4)*exp(3*x). - G. C. Greubel, May 19 2021
From Amiram Eldar, Sep 22 2022: (Start)
Sum_{n>=0} 1/a(n) = 40 - 96*log(3/2).
Sum_{n>=0} (-1)^n/a(n) = 768*log(4/3) - 220. (End)
MAPLE
seq(3^n*binomial(n+4, 4), n=0..30); # Zerinvary Lajos, Jun 12 2008
MATHEMATICA
CoefficientList[Series[1/(1-3x)^5, {x, 0, 30}], x] (* Harvey P. Dale, Jun 13 2017 *)
PROG
(Sage) [3^n*binomial(n+4, 4) for n in range(30)] # Zerinvary Lajos, Mar 10 2009
(Magma) [3^n* Binomial(n+4, 4): n in [0..30]]; // Vincenzo Librandi, Oct 14 2011
CROSSREFS
Sequences of the form 3^n*binomial(n+m, m): A000244 (m=0), A027471 (m=1), A027472 (m=2), A036216 (m=3), this sequence (m=4), A036219 (m=5), A036220 (m=6), A036221 (m=7), A036222 (m=8), A036223 (m=9), A172362 (m=10).
Sequence in context: A027630 A027629 A023013 * A022643 A125378 A254409
KEYWORD
easy,nonn
STATUS
approved