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A034709 Numbers divisible by their last digit. 31

%I

%S 1,2,3,4,5,6,7,8,9,11,12,15,21,22,24,25,31,32,33,35,36,41,42,44,45,48,

%T 51,52,55,61,62,63,64,65,66,71,72,75,77,81,82,84,85,88,91,92,93,95,96,

%U 99,101,102,104,105,111,112,115,121,122,123,124,125,126,128,131,132

%N Numbers divisible by their last digit.

%C Union of A017281, A017293, A139222, A139245, A017329, A139249, A139264, A139279 and A139280. - _Reinhard Zumkeller_, Jun 22 2008

%C The differences between consecutive terms repeat with period 1177 and the corresponding terms differ by 2520 = LCM(1,2,...,9). In other words, a(k*1177+i) = 2520*k + a(i). - _Giovanni Resta_, Aug 20 2015

%H Reinhard Zumkeller, <a href="/A034709/b034709.txt">Table of n, a(n) for n = 1..10000</a>

%p N:= 1000: # to get all terms <= N

%p sort([seq(seq(ilcm(10,d)*x+d, x=0..floor((N-d)/ilcm(10,d))), d=1..9)]); # _Robert Israel_, Aug 20 2015

%t dldQ[n_]:=Module[{idn=IntegerDigits[n],last1},last1=Last[idn]; last1!= 0&&Divisible[n,last1]]; Select[Range[150],dldQ] (* _Harvey P. Dale_, Apr 25 2011 *)

%o (Haskell)

%o import Data.Char (digitToInt)

%o a034709 n = a034709_list !! (n-1)

%o a034709_list =

%o filter (\i -> i `mod` 10 > 0 && i `mod` (i `mod` 10) == 0) [1..]

%o -- _Reinhard Zumkeller_, Jun 19 2011

%o (Python)

%o A034709_list = [n for n in range(1, 1000) if n % 10 and not n % (n % 10)]

%o # _Chai Wah Wu_, Sep 18 2014

%o (PARI) for(n=1,200,if(n%10,if(!(n%digits(n)[#Str(n)]),print1(n,", ")))) # _Derek Orr_, Sep 19 2014

%Y Cf. A002706, A034838, A007602,

%K nonn,base,easy,nice

%O 1,2

%A _Erich Friedman_

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Last modified September 16 10:46 EDT 2019. Contains 327094 sequences. (Running on oeis4.)