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%I #13 Oct 30 2021 13:23:17
%S 10,30,31,32,69,70,71,72,73,74,133,134,135,136,137,138,139,140,227,
%T 228,229,230,231,232,233,234,235,236,237,238,358,359,360,361,362,363,
%U 364,365,366,367,368,369,370,371,372,373,532,533,534,535,536,537,538,539
%N Fractional part of cube root of a(n) starts with digit 1.
%o (Python)
%o from sympy import integer_nthroot
%o def ok(n): return integer_nthroot(1000*n, 3)[0]%10 == 1
%o print([k for k in range(540) if ok(k)]) # _Michael S. Branicky_, Oct 30 2021
%Y Cf. A034127.
%K nonn,easy,base
%O 1,1
%A _Patrick De Geest_, Sep 15 1998
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