OFFSET
1,1
PROG
(Python)
from sympy import integer_nthroot
def ok(n): return integer_nthroot(1000*n, 3)[0]%10 == 1
print([k for k in range(540) if ok(k)]) # Michael S. Branicky, Oct 30 2021
CROSSREFS
KEYWORD
nonn,easy,base
AUTHOR
Patrick De Geest, Sep 15 1998
STATUS
approved