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1(01)^(2n+1).
1

%I #17 Aug 18 2019 11:40:23

%S 101,1010101,10101010101,101010101010101,1010101010101010101,

%T 10101010101010101010101,101010101010101010101010101,

%U 1010101010101010101010101010101,10101010101010101010101010101010101

%N 1(01)^(2n+1).

%D C. Ashbacher, Problem 514, The Pentagon, Vol. 57, No. 1, Fall 1997, p. 36

%D M. Le, On Smarandache Pierce Chain, Smarandache Notions Journal, Vol. 10, No. 1-2-3, 1999, 154-155.

%D Florentin Smarandache, Properties of the numbers, ASU Special Collections, 1973.

%H Eric Weisstein's World of Mathematics, <a href="http://mathworld.wolfram.com/SmarandacheSequences.html">Smarandache Sequences</a>

%H <a href="/index/Rec">Index entries for linear recurrences with constant coefficients</a>, signature (10001,-10000).

%F a(n) = 101 (10^(4n) - 1)/(10^4 - 1).

%t 101(10^(4Range[10]) - 1)/9999 (* _Alonso del Arte_, May 20 2017 *)

%t LinearRecurrence[{10001,-10000},{101,1010101},20] (* _Harvey P. Dale_, Aug 18 2019 *)

%K nonn,easy

%O 0,1

%A J. Castillo (arp(AT)cia-g.com)

%E More terms from _James A. Sellers_