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%I #7 Mar 04 2015 15:12:28
%S 1561,1579,1621,1741,1981,2371,2661,2683,2719,2734,2854,3292,3541,
%T 3577,3613,3637,3669,3754,3826,4195,4219,4291,4363,4391,4468,4513,
%U 4957,5129,5146,5161,5169,5416,5479,5533,5710,5861,5867,6269,6313,6389,6509,6542
%N Period of continued fraction for sqrt(n) contains exactly 32 ones.
%t cf32Q[n_]:=Module[{s=Sqrt[n]},If[IntegerQ[s],1,Count[ContinuedFraction[s][[2]],1]]==32]; Select[Range[7000],cf32Q] (* _Harvey P. Dale_, Mar 04 2015 *)
%K nonn
%O 1,1
%A _David W. Wilson_