|
| |
|
|
A026569
|
|
a(n)=T(n,n), T given by A026568. Also a(n) = number of integer strings s(0),...,s(n) counted by T, such that s(n)=0.
|
|
7
| |
|
|
1, 1, 3, 5, 13, 27, 67, 153, 375, 893, 2189, 5319, 13089, 32155, 79479, 196573, 487833, 1212135, 3018355, 7525585, 18792303, 46980373, 117589689, 294613155, 738844719, 1854484305, 4658460165, 11710592711, 29458662005, 74151824271
(list; graph; refs; listen; history; internal format)
|
|
|
|
OFFSET
| 0,3
|
|
|
LINKS
| Vincenzo Librandi, Table of n, a(n) for n = 0..200
J. W. Layman, The Hankel Transform and Some of its Properties, J. Integer Sequences, 4 (2001), #01.1.5.
|
|
|
FORMULA
| a(n) = sum(k=0..floor(n/2), binomial(2*k, k)*binomial(n-k, k) ) - Paul Barry, Sep 09 2004
G.f.: sqrt(1/((1-x)*(1-x-4*x^2))). - Ralf Stephan, Jan 08 2004
a(n) = 1/n*((2*n-1)*a(n-1)+(3*n-3)*a(n-2)-(4*n-6)*a(n-3)). - Vladeta Jovovic (vladeta(AT)eunet.rs), Mar 12 2005
a(n) = sum(k=0..n, C(k, n-k)*C(2*(n-k), n-k)). - Paul Barry, Jul 30 2005
G.f.: 1/(1-x-2x^2/(1-0x-x^2/(1-x-x^2/(1-0x-2x^2/(1-x-x^2/.... (continued fraction). [From Paul Barry, Dec 07 2008]
Conjecture: n*a(n) +(1-2n)*a(n-1) +3*(1-n)*a(n-2) +2*(2n-3)*a(n-3) = 0. - R. J. Mathar, Nov 16 2011
|
|
|
MATHEMATICA
| CoefficientList[Series[Sqrt[1/((1-x)(1-x-4x^2))], {x, 0, 30}], x] (* From Harvey P. Dale, Oct 06 2011 *)
|
|
|
CROSSREFS
| Sequence in context: A084173 A190570 A000631 * A035082 A005198 A160823
Adjacent sequences: A026566 A026567 A026568 * A026570 A026571 A026572
|
|
|
KEYWORD
| nonn
|
|
|
AUTHOR
| Clark Kimberling (ck6(AT)evansville.edu)
|
| |
|
|