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 A026272 a(n) = smallest k such that k=a(n-k-1) is the only appearance of k so far; if there is no such k, then a(n) = least positive integer that has not yet appeared. 11
 1, 2, 1, 3, 2, 4, 5, 3, 6, 7, 4, 8, 5, 9, 10, 6, 11, 7, 12, 13, 8, 14, 15, 9, 16, 10, 17, 18, 11, 19, 20, 12, 21, 13, 22, 23, 14, 24, 15, 25, 26, 16, 27, 28, 17, 29, 18, 30, 31, 19, 32, 20, 33, 34, 21, 35, 36, 22, 37, 23, 38, 39, 24, 40, 41, 25 (list; graph; refs; listen; history; text; internal format)
 OFFSET 1,2 COMMENTS This sequence displays every positive integer exactly twice and the gap between the two occurrences of n contains exactly n other values. The first occurrence of n precedes the first occurrence of n+1. (cont.) Also related to the Wythoff array (A035513) and the Para-Fibonacci sequence (A035513) where every positive integer is displayed exactly once in the whole array. Take any integer n in A026272 and let C = number of terms from the beginning of the sequence to the second occurrence of n. Then C = (2nd term after n in the applicable sequence for n in A035513). (cont.) Also in the second occurrence of n in A026272, let N=n ( - one term) = (first term value after n in the applicable sequence for n in A035513). In this format the second occurrence of n in A026272 will produce in A035513, n itself and two of the succeeding terms of n in the Wythoff array where every positive integer can only be displayed once. (cont.) In A026272 if |a(n)-a(n+1)| > 10 then phi ~ a(n)/|a(n)-a(n+1)|. When n -> infinity it will converge to phi. - Daniel Joyce, Apr 13 2001 Or, put a copy of n in A000027 n places further along! - Zak Seidov, May 24 2008 Another version would prefix this sequence with two leading 0's (see the Angelini reference). If we use this form and write down the indices of the two 0's, the two 1's, the two 2's, the two 3's, etc., then we get A072061. - Jacques ALARDET, Jul 26 2008 REFERENCES E. Angelini, "Jeux de suites", in Dossier Pour La Science, pp. 32-35, Volume 59 (Jeux math'), April/June 2008, Paris. LINKS Zak Seidov, Table of n, a(n) for n = 1..1000 FORMULA a(n) = A026242(n+2) - 1 = A026350(n+3) - 2 = A026354(n+4) - 3. MATHEMATICA s=Range[1000]; n=0; Do[n++; s=Insert[s, n, Position[s, n][[1]]+n+1], {500}]; A026272=Take[s, 1000] - Zak Seidov, May 24 2008 PROG (PARI) A026272=apply(t->t-1, A026242[3..-1]) \\ Use vecextract(A026242, "3..") in PARI versions < 2.7. - M. F. Hasler, Sep 17 2014 CROSSREFS Cf. A000027, A035513, A014552, A176127. Sequence in context: A094173 A214370 A227859 * A193564 A022447 A117194 Adjacent sequences:  A026269 A026270 A026271 * A026273 A026274 A026275 KEYWORD nonn,easy,nice AUTHOR EXTENSIONS Edited by Max Alekseyev, May 31 2011 STATUS approved

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Last modified February 20 00:28 EST 2019. Contains 320329 sequences. (Running on oeis4.)