login
a(n) = [ sum of 1/{k*e} ] for k = 1,2,...,n, where {x} := x - [ x ].
2

%I #9 Aug 03 2014 14:27:15

%S 1,3,10,11,12,16,51,53,55,60,62,63,66,84,85,87,92,93,95,97,109,111,

%T 112,117,118,119,122,131,132,134,137,138,140,142,149,151,152,156,233,

%U 234,236,242,243,245,248,273,274,276,281,282,284,287,301,302,304,309,310,311,314,324

%N a(n) = [ sum of 1/{k*e} ] for k = 1,2,...,n, where {x} := x - [ x ].

%H Clark Kimberling, <a href="/A024575/b024575.txt">Table of n, a(n) for n = 1..1000</a>

%t Table[Floor[Sum[1/FractionalPart[k*E], {k, n}]], {n, 100}] (* _Clark Kimberling_, Aug 15 2012 *)

%Y Cf. A024574.

%K nonn

%O 1,2

%A _Clark Kimberling_