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A024573
a(n) = floor(1/frac(n*e)).
5
1, 2, 6, 1, 1, 3, 35, 1, 2, 5, 1, 1, 2, 17, 1, 2, 4, 1, 1, 2, 11, 1, 1, 4, 1, 1, 2, 8, 1, 1, 3, 1, 1, 2, 7, 1, 1, 3, 76, 1, 2, 5, 1, 1, 3, 24, 1, 2, 5, 1, 1, 2, 14, 1, 1, 4, 1, 1, 2, 10, 1, 1, 3, 1, 1, 2, 8, 1, 1, 3, 1, 1, 2, 6, 1, 1, 3, 38, 1, 2, 5, 1, 1, 2, 18, 1, 2, 4, 1, 1, 2, 12, 1, 1, 4, 1, 1, 2, 9, 1
OFFSET
1,2
COMMENTS
The sequence is well defined, since frac(n*e)>0 for n>0.
Let b(n,m) = |{a(k)| 1<=k<=n, a(k)>=m}| be the number of the first n terms which are >= m >= 1.
Then, lim b(n,m)/n = 1/m for n-->oo since frac(n*e) is uniformly distributed. - Hieronymus Fischer, Apr 15 2012
LINKS
MATHEMATICA
f[n_] := Floor[1/FractionalPart[n*E]]; Array[f, 100] (* Robert G. Wilson v, Apr 17 2012 *)
CROSSREFS
Sequence in context: A205015 A204937 A126749 * A191359 A339766 A289203
KEYWORD
nonn
STATUS
approved