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a(n) = 10^n - n^12.
2

%I #21 Jul 08 2024 21:42:50

%S 1,9,-3996,-530441,-16767216,-244040625,-2175782336,-13831287201,

%T -68619476736,-281429536481,-990000000000,-3038428376721,

%U -7916100448256,-13298085122481,43306087624704,870253662109375,9718525023289344

%N a(n) = 10^n - n^12.

%H Vincenzo Librandi, <a href="/A024126/b024126.txt">Table of n, a(n) for n = 0..300</a>

%H <a href="/index/Rec#order_14">Index entries for linear recurrences with constant coefficients</a>, signature (23,-208,1066,-3575,8437,-14586,18876,-18447,13585,-7436,2938,-793,131,-10).

%t Table[10^n-n^12,{n,0,20}] (* _Harvey P. Dale_, Jul 18 2011 *)

%o (Magma) [10^n-n^12: n in [0..20]]; // _Vincenzo Librandi_, Jul 01 2011

%o (PARI) a(n)=10^n-n^12 \\ _Charles R Greathouse IV_, Jul 01 2011

%K sign,easy

%O 0,2

%A _N. J. A. Sloane_