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a(n) = 4^n - n^8.
2

%I #12 Sep 08 2022 08:44:48

%S 1,3,-240,-6497,-65280,-389601,-1675520,-5748417,-16711680,-42784577,

%T -98951424,-210164577,-413204480,-748621857,-1207353600,-1489148801,0,

%U 10204111743,57699516160,257894343903,1073911627776

%N a(n) = 4^n - n^8.

%H Vincenzo Librandi, <a href="/A024044/b024044.txt">Table of n, a(n) for n = 0..500</a>

%t Table[4^n-n^8,{n,0,20}] (* _Harvey P. Dale_, Sep 04 2018 *)

%o (Magma) [4^n-n^8: n in [0..30]]; // _Vincenzo Librandi_, Jul 02 2011

%K sign,easy

%O 0,2

%A _N. J. A. Sloane_