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a(n) = 3^n - n^7.
2

%I #12 Jan 22 2024 22:38:20

%S 1,2,-119,-2160,-16303,-77882,-279207,-821356,-2090591,-4763286,

%T -9940951,-19310024,-35300367,-61154194,-100630535,-156510468,

%U -225388735,-281198510,-224799543,268389728,2206784401

%N a(n) = 3^n - n^7.

%H Vincenzo Librandi, <a href="/A024030/b024030.txt">Table of n, a(n) for n = 0..200</a>

%t Table[3^n-n^7,{n,0,20}] (* _Harvey P. Dale_, Jan 22 2024 *)

%o (Magma) [3^n-n^7: n in [0..35]]; // _Vincenzo Librandi_, May 13 2011

%K sign

%O 0,2

%A _N. J. A. Sloane_