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A023402 If any power of 2 ends with k 3's and 4's, they must be the first k elements of this sequence in reverse order. 2
4, 4, 3, 3, 3, 4, 3, 3, 3, 3, 4, 3, 3, 3, 4, 3, 4, 4, 3, 4, 4, 4, 4, 3, 4, 4, 3, 3, 4, 3, 3, 3, 4, 3, 3, 3, 3, 3, 3, 4, 3, 3, 4, 3, 4, 3, 3, 4, 4, 4, 3, 4, 3, 4, 3, 3, 4, 4, 3, 4, 3, 4, 3, 3, 3, 4, 3, 3, 3, 4, 3, 3, 4, 4, 4, 3, 4, 4, 4, 4, 4, 3, 3, 3, 3, 4, 3, 4, 3, 4, 4, 3, 3, 4, 4, 3, 3, 4, 3, 3, 4, 3, 4, 3, 3, 3, 4, 4 (list; graph; refs; listen; history; internal format)
OFFSET

0,1

COMMENTS

Conjecture: a(n) = 3rd divisor of smallest number having exactly n+2 divisors, a(n)=T(n+2,3), T as defined in A081532. - Reinhard Zumkeller (reinhard.zumkeller(AT)gmail.com), Jul 18 2003

CROSSREFS

Cf. A035014.

Sequence in context: A194668 A138160 A120886 * A073261 A020805 A200587

Adjacent sequences:  A023399 A023400 A023401 * A023403 A023404 A023405

KEYWORD

nonn

AUTHOR

David W. Wilson (davidwwilson(AT)comcast.net)

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Last modified February 17 04:58 EST 2012. Contains 205985 sequences.