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A022912 Arrange the nontrivial binomial coefficients C(m,k) (2 <= k <= m/2) in increasing order (not removing duplicates); record the sequence of k's. 4
2, 2, 2, 3, 2, 2, 3, 2, 2, 2, 3, 2, 4, 2, 3, 2, 2, 2, 3, 4, 2, 2, 3, 2, 2, 2, 4, 3, 2, 5, 2, 2, 3, 2, 2, 4, 2, 3, 2, 2, 2, 3, 5, 2, 4, 2, 2, 3, 2, 2, 2, 2, 3, 2, 4, 2, 2, 5, 3, 2, 2, 2, 6, 2, 3, 2, 4, 2, 2, 2, 3, 2, 2, 2, 5, 2, 3, 4, 2, 2, 2, 2, 3, 2, 2, 2, 6, 2, 3, 4, 2, 2, 2, 5, 2, 3, 2, 2, 2 (list; graph; refs; listen; history; text; internal format)
OFFSET

1,1

COMMENTS

In case of duplicates, the k values are listed in increasing order.  Thus a(18)=2 and a(19)=3 corresponding to binomial(16,2)=binomial(10,3)=120.

LINKS

Robert Israel, Table of n, a(n) for n = 1..10000

FORMULA

A319382(n) = binomial(A022911(n),a(n)). - Robert Israel, Sep 18 2018

MAPLE

N:= 10000: # for binomial(n, k) values <= N

Res:= NULL:

for n from 2 while n*(n-1)/2 <= N do

  for k from 2 to n/2 do

    v:= binomial(n, k);

    if v > N then break fi;

    Res:= Res, [v, n, k]

od od:

Res:= sort([Res], proc(p, q) if p[1]<>q[1] then  p[1]<q[1]

  elif p[2]<>q[2] then p[2]>q[2]

fi end proc): map(t -> t[3], Res); # Robert Israel, Sep 18 2018

CROSSREFS

Cf. A003015, A006987, A022911, A319382.

Sequence in context: A325273 A279408 A135592 * A318955 A173883 A022922

Adjacent sequences:  A022909 A022910 A022911 * A022913 A022914 A022915

KEYWORD

nonn

AUTHOR

Clark Kimberling

EXTENSIONS

Corrected by Robert Israel, Sep 18 2018

STATUS

approved

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Last modified April 23 02:15 EDT 2019. Contains 322380 sequences. (Running on oeis4.)