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A022095 Fibonacci sequence beginning 1 5. 16
1, 5, 6, 11, 17, 28, 45, 73, 118, 191, 309, 500, 809, 1309, 2118, 3427, 5545, 8972, 14517, 23489, 38006, 61495, 99501, 160996, 260497, 421493, 681990, 1103483, 1785473, 2888956, 4674429, 7563385, 12237814, 19801199, 32039013, 51840212, 83879225, 135719437 (list; graph; refs; listen; history; internal format)
OFFSET

0,2

COMMENTS

a(n-1)=sum(P(5;n-1-k,k),k=0..ceiling((n-1)/2)), n>=1, with a(-1)=4. These are the sums of the SW-NE diagonals in P(5;n,k), the (5,1) Pascal triangle A093562. Observation by Paul Barry (pbarry(AT)wit.ie, Apr 29 2004. Proof via recursion relations and comparison of inputs. Also sums of the SW-NE diagonals in the (1,4)-Pascal triangle A095666.

In general, for a Fibonacci sequence beginning with 1,b we have

a(n)=(2^(-1-n)((1-Sqrt[5])^n(1+Sqrt[5]-2b)+(1+Sqrt[5])^n(-1+Sqrt[5]+2b)))/Sqrt[5] - Herbert Kociemba(kociemba(AT)t-online.de), Dec 18 2011

LINKS

Index entries for sequences related to linear recurrences with constant coefficients, signature (1,1)

Tanya Khovanova, Recursive Sequences

FORMULA

a(n)= a(n-1)+a(n-2), n>=2, a(0)=1, a(1)=5. a(-1):=4.

G.f.: (1+4*x)/(1-x-x^2).

Row sums of triangle A131776 starting (1, 5, 6, 11, 17, 28,...). - Gary W. Adamson (qntmpkt(AT)yahoo.com), Jul 14 2007

a(n)=4*fibonacci(n)+fibonacci(n+1), n>=1 - Zerinvary Lajos (zerinvarylajos(AT)yahoo.com), Oct 05 2007, corrected by R. J. Mathar, Apr 07 2011

a(n-1)=((1+sqrt5)^n-(1-sqrt5)^n)/(2^n*sqrt5)+ 2*((1+sqrt5)^(n-1)-(1-sqrt5)^(n-1))/(2^(n-2)*sqrt5). [From Al Hakanson (hawkuu(AT)gmail.com), Jan 14 2009]

a(n)= 4*Fibonacci(n+2)-3*Fibonacci(n+1) [From Gary Detlefs (gdetlefs(AT)aol.com) Dec 21 2010]

MAPLE

a:=n->4*fibonacci(n)+fibonacci(n+1): seq(a(n), n=0..32); - Zerinvary Lajos (zerinvarylajos(AT)yahoo.com), Oct 05 2007

MATHEMATICA

a={}; b=1; c=5; AppendTo[a, b]; AppendTo[a, c]; Do[b=b+c; AppendTo[a, b]; c=b+c; AppendTo[a

, c], {n, 1, 9, 1}]; a (Vladimir Orlovsky, Jul 22 2008)

PROG

(PARI) a(n)=fibonacci(n-1)+5*fibonacci(n) \\ Charles R Greathouse IV, Jun 05, 2011

CROSSREFS

a(n) = A101220(4, 0, n+1).

a(n) = A109754(4, n+1).

Cf. A131776.

Sequence in context: A136974 A101187 A070373 * A042531 A042839 A041373

Adjacent sequences:  A022092 A022093 A022094 * A022096 A022097 A022098

KEYWORD

nonn,easy

AUTHOR

N. J. A. Sloane (njas(AT)research.att.com).

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Last modified February 14 09:35 EST 2012. Contains 205614 sequences.