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1/88 = sum (12^i/100^(i+1)), i >= 0,
1/988 = sum (12^i/1000^(i+1)), i >= 0, (this sequence)
1/9988 = sum (12^i/10000^(i+1)), i >= 0, ... - Daniel Forgues, Oct 28 2011
Table of n, a(n) for n=0..98.
Sequence in context: A052947 A159287 A252448 * A261035 A080030 A125156
Adjacent sequences: A021989 A021990 A021991 * A021993 A021994 A021995
N. J. A. Sloane.