OFFSET
0,4
COMMENTS
Generalization:
1/1 = sum (9^i/10^(i+1)), i >= 0,
1/91 = sum (9^i/100^(i+1)), i >= 0, (this sequence)
1/991 = sum (9^i/1000^(i+1)), i >= 0,
1/9991 = sum (9^i/1000^(i+1)), i >= 0, ... - Daniel Forgues, Oct 28 2011
LINKS
Index entries for linear recurrences with constant coefficients, signature (1, 0, -1, 1).
CROSSREFS
KEYWORD
nonn,cons
AUTHOR
STATUS
approved