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A020924
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Expansion of 1/(1-4*x)^(13/2).
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3
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1, 26, 390, 4420, 41990, 352716, 2704156, 19315400, 130378950, 840219900, 5209363380, 31256180280, 182327718300, 1037865473400, 5782393351800, 31610416989840, 169905991320390, 899502306990300, 4697400936504900, 24228699567235800, 123566367792902580, 623715951716555880
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OFFSET
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0,2
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LINKS
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FORMULA
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a(n) = (2*n+11)*(2*n+9)*(2*n+7)*(2*n+5)*(2*n+3)*(2*n+1)*Binomial(2*n, n)/10395. - Vincenzo Librandi, Jul 05 2013
Boas-Buck recurrence: a(n) = (26/n)*Sum_{k=0..n-1} 4^(n-k-1)*a(k), n >= 1, a(0) = 1. Proof from a(n) = A046521(n+6, 6). See a comment there. - Wolfdieter Lang, Aug 10 2017
a(n) = 45*binomial(n+6,n)*binomial(2*n+12,n+6)/(4*binomial(2*n,n)). - G. C. Greubel, Jul 20 2019
Sum_{n>=0} 1/a(n) = 1018468/315 - 594*sqrt(3)*Pi.
Sum_{n>=0} (-1)^n/a(n) = 27500*sqrt(5)*log(phi) - 1864148/63, where phi is the golden ratio (A001622). (End)
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MATHEMATICA
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CoefficientList[Series[1/(1-4x)^(13/2), {x, 0, 30}], x] (* Vincenzo Librandi, Jul 05 2013 *)
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PROG
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(Magma) [&*[2*n+i: i in [1..11 by 2]]*Binomial(2*n, n)/10395: n in [0..20]]; // Vincenzo Librandi, Jul 05 2013
(Magma) [Binomial(n+6, n)*Binomial(2*n+12, n+6)/924: n in [0..30]]; // G. C. Greubel, Jul 20 2019
(PARI) vector(30, n, n--; m=n+6; binomial(m, n)*binomial(2*m, m)/924)
(Sage) [binomial(n+6, n)*binomial(2*n+12, n+6)/924 for n in (0..30)] # G. C. Greubel, Jul 20 2019
(GAP) List([0..30], n-> Binomial(n+6, n)*Binomial(2*n+12, n+6)/924); # G. C. Greubel, Jul 20 2019
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CROSSREFS
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KEYWORD
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nonn,easy
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AUTHOR
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STATUS
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approved
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