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Ceiling of Gamma(n + 9/11)/Gamma(9/11).
2

%I #13 Mar 08 2018 16:15:13

%S 1,1,2,5,17,78,449,3060,23920,210930,2070941,22403815,264772350,

%T 3393900116,46897528867,694936109572,10992625733215,184875978240421,

%U 3294153794102035,61989985034465560,1228528794319408361,25575735809013137690,558016054014832095049

%N Ceiling of Gamma(n + 9/11)/Gamma(9/11).

%p Digits:= 64: f:= proc(n, x) ceil(GAMMA(n+x)/GAMMA(x)) end: seq(f(n, 9/11), n=0..25);

%t Ceiling[Gamma[Range[0, 19] + 9/11]/Gamma[9/11]] (* _Alonso del Arte_, Mar 01 2018 *)

%K nonn

%O 0,3

%A _Simon Plouffe_