%I #31 Sep 08 2022 08:44:43
%S 1,99,4950,166650,4249575,87541245,1517381580,22760723700,
%T 301579589025,3585446225075,38722819230810,383707936014390,
%U 3517322746798575,30032524991895525,240260199935164200,1809960172844903640,12895966231519938435,87237418624987818825
%N Binomial coefficients C(n,98).
%H Michael De Vlieger, <a href="/A017762/b017762.txt">Table of n, a(n) for n = 98..10000</a>
%F From _G. C. Greubel_, Nov 12 2018: (Start)
%F G.f.: x^98/(1-x)^99.
%F E.g.f.: x^98*exp(x)/98!. (End)
%F From _Amiram Eldar_, Dec 20 2020: (Start)
%F Sum_{n>=98} 1/a(n) = 98/97.
%F Sum_{n>=98} (-1)^n/a(n) = A001787(98)*log(2) - A242091(98)/97! = 15528719852795810168334614265856*log(2) - 1914409165727592211172313915606799843601351282016393511620277508464529 / 177858100075797135623810737079878325400 = 0.9900952340... (End)
%p A017762:=n->binomial(n,98); seq(A017762(k), k=98..200); # _Wesley Ivan Hurt_, Nov 05 2013
%t Table[Binomial[n, 98], {n, 98, 120}] (* _Vladimir Joseph Stephan Orlovsky_, Jul 15 2011 *)
%o (Sage) [binomial(n, 98) for n in range(98,113)] # _Zerinvary Lajos_, May 23 2009
%o (PARI) a(n)=binomial(n,98) \\ _Charles R Greathouse IV_, Jun 28 2012
%o (Magma) [Binomial(n,98): n in [98..115]]; // _G. C. Greubel_, Nov 12 2018
%Y Cf. A001787, A242091.
%K nonn,easy
%O 98,2
%A _N. J. A. Sloane_