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a(n) = 12*n + 9.
20

%I #77 Feb 25 2023 20:57:39

%S 9,21,33,45,57,69,81,93,105,117,129,141,153,165,177,189,201,213,225,

%T 237,249,261,273,285,297,309,321,333,345,357,369,381,393,405,417,429,

%U 441,453,465,477,489,501,513,525,537,549,561,573,585,597,609,621,633

%N a(n) = 12*n + 9.

%C Numbers k such that k mod 2 = (k+1) mod 3 = 1 and (k+2) mod 4 != 1. - _Klaus Brockhaus_, Jun 15 2004

%C For n > 3, the number of squares on the infinite 3-column chessboard at <= n knight moves from any fixed point. - _Ralf Stephan_, Sep 15 2004

%C A016946 is the subsequence of squares (for n = 3*k*(k+1) = A028896(k), then a(n) = (6k+3)^2 = A016946(k)). - _Bernard Schott_, Apr 05 2021

%H Tanya Khovanova, <a href="http://www.tanyakhovanova.com/RecursiveSequences/RecursiveSequences.html">Recursive Sequences</a>.

%H <a href="/index/Rec#order_02">Index entries for linear recurrences with constant coefficients</a>, signature (2,-1).

%F a(n) = 6*(4*n+1) - a(n-1) (with a(0)=9). - _Vincenzo Librandi_, Dec 17 2010

%F A089911(2*a(n)) = 4. - _Reinhard Zumkeller_, Jul 05 2013

%F G.f.: (9 + 3*x)/(1 - x)^2. - _Alejandro J. Becerra Jr._, Jul 08 2020

%F Sum_{n>=0} (-1)^n/a(n) = (Pi + log(3-2*sqrt(2)))/(12*sqrt(2)). - _Amiram Eldar_, Dec 12 2021

%F E.g.f.: 3*exp(x)*(3 + 4*x). - _Stefano Spezia_, Feb 25 2023

%t 12*Range[0,200]+9 (* _Vladimir Joseph Stephan Orlovsky_, Feb 19 2011 *)

%t LinearRecurrence[{2,-1},{9,21},60] (* _Harvey P. Dale_, Apr 14 2019 *)

%o (Sage) [i+9 for i in range(525) if gcd(i,12) == 12] # _Zerinvary Lajos_, May 21 2009

%o (Haskell)

%o a017629 = (+ 9) . (* 12) -- _Reinhard Zumkeller_, Jul 05 2013

%o (PARI) a(n)=12*n+9 \\ _Charles R Greathouse IV_, Jul 10 2016

%Y Subsequences include A072065, A016945, A016813, A008585, and A005408.

%Y Cf. A008594, A017533, A017545, A017137, A004767, A001019, A028896, A016946, A089911.

%K nonn,easy

%O 0,1

%A _N. J. A. Sloane_