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a(n) = (12n+4)^7.
0

%I #13 Dec 30 2024 22:44:21

%S 16384,268435456,13492928512,163840000000,1028071702528,4398046511104,

%T 14645194571776,40867559636992,100000000000000,221068140740608,

%U 450766669594624,860542568759296,1555363874947072,2684354560000000,4453476124377088,7140436495826944,11112006825558016

%N a(n) = (12n+4)^7.

%H <a href="/index/Rec#order_08">Index entries for linear recurrences with constant coefficients</a>, signature (8,-28,56,-70,56,-28,8,-1).

%F From _Amiram Eldar_, Jul 14 2024: (Start)

%F a(n) = A001015(A017569(n)) = A017569(n)^7.

%F a(n) = 16384 * A016783(n).

%F Sum_{n>=0} 1/a(n) = 7*Pi^7/(403107840*sqrt(3)) + 1093*zeta(7)/35831808. (End)

%t a[n_] := (12*n + 4)^7; Array[a, 20, 0] (* _Amiram Eldar_, Jul 14 2024 *)

%Y Cf. A001015, A013665, A016783, A017569.

%K nonn,easy

%O 0,1

%A _N. J. A. Sloane_

%E More terms from _Amiram Eldar_, Jul 14 2024