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a(n) = (11*n)^5.
1

%I #14 Sep 08 2022 08:44:42

%S 0,161051,5153632,39135393,164916224,503284375,1252332576,2706784157,

%T 5277319168,9509900499,16105100000,25937424601,40074642432,

%U 59797108943,86617093024,122298103125,168874213376

%N a(n) = (11*n)^5.

%H Vincenzo Librandi, <a href="/A017393/b017393.txt">Table of n, a(n) for n = 0..10000</a>

%H <a href="/index/Rec#order_06">Index entries for linear recurrences with constant coefficients</a>, signature (6, -15, 20, -15, 6, -1).

%t (11 Range[0,20])^5 (* or *) LinearRecurrence[{6,-15,20,-15,6,-1},{0,161051,5153632,39135393,164916224,503284375},20] (* _Harvey P. Dale_, May 20 2019 *)

%o (Magma) [(11*n)^5: n in [0..30]]; // _Vincenzo Librandi_, Sep 02 2011

%K nonn,easy

%O 0,2

%A _N. J. A. Sloane_