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a(n) = (10*n + 9)^12.
1

%I #18 Sep 08 2022 08:44:42

%S 282429536481,2213314919066161,353814783205469041,

%T 12381557655576425121,191581231380566414401,1779197418239532716881,

%U 11646329922777311412561,59091511031674153381441,246990403565262140303521,886384871716129280658801

%N a(n) = (10*n + 9)^12.

%H Vincenzo Librandi, <a href="/A017388/b017388.txt">Table of n, a(n) for n = 0..10000</a>

%H <a href="/index/Rec#order_13">Index entries for linear recurrences with constant coefficients</a>, signature (13, -78, 286, -715, 1287, -1716, 1716, -1287, 715, -286, 78, -13, 1).

%t (10*Range[0,20]+9)^12 (* _Harvey P. Dale_, Dec 06 2013 *)

%o (Magma) [(10*n+9)^12: n in [0..20]]; // _Vincenzo Librandi_, Sep 01 2011

%o (PARI) vector(20, n, n--; (10*n + 9)^12) \\ _G. C. Greubel_, Nov 11 2018

%K nonn,easy

%O 0,1

%A _N. J. A. Sloane_