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%I #25 Apr 18 2023 05:02:03
%S 244140625,129746337890625,59604644775390625,3379220508056640625,
%T 68952523554931640625,766217865410400390625,5688009063105712890625,
%U 31676352024078369140625,142241757136172119140625,540360087662636962890625,1795856326022129150390625,5350250105473711181640625
%N a(n) = (10*n + 5)^12.
%H Vincenzo Librandi, <a href="/A017340/b017340.txt">Table of n, a(n) for n = 0..10000</a>
%H <a href="/index/Rec#order_13">Index entries for linear recurrences with constant coefficients</a>, signature (13,-78,286,-715,1287,-1716,1716,-1287,715,-286,78,-13,1).
%F G.f.: -244140625*(x^12 + 531428*x^11 + 237231970*x^10 + 10708911188*x^9 + 121383780207*x^8 + 477020564424*x^7 + 743288515164*x^6 + 477020564424*x^5 + 121383780207*x^4 + 10708911188*x^3 + 237231970*x^2 + 531428*x + 1)/(x-1)^13. - _Colin Barker_, Nov 14 2012
%F From _Amiram Eldar_, Apr 18 2023: (Start)
%F a(n) = A017329(n)^12.
%F a(n) = 5^12 * A016764(n).
%F Sum_{n>=0} 1/a(n) = 691*Pi^12/155925000000000000. (End)
%t (10*Range[0,20]+5)^12 (* _Harvey P. Dale_, May 09 2022 *)
%o (Magma) [(10*n+5)^12: n in [0..10]]; // _Vincenzo Librandi_, Aug 02 2011
%Y Cf. A016764, A017329.
%K nonn,easy
%O 0,1
%A _N. J. A. Sloane_
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