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a(n) = (10*n + 1)^11.
1

%I #17 Sep 08 2022 08:44:42

%S 1,285311670611,350277500542221,25408476896404831,550329031716248441,

%T 6071163615208263051,43513917611435838661,231122292121701565271,

%U 984770902183611232881,3543686674874777831491,11156683466653165551101

%N a(n) = (10*n + 1)^11.

%H Vincenzo Librandi, <a href="/A017291/b017291.txt">Table of n, a(n) for n = 0..1000</a>

%H <a href="/index/Rec#order_12">Index entries for linear recurrences with constant coefficients</a>, signature (12, -66, 220, -495, 792, -924, 792, -495, 220, -66, 12, -1).

%t (10Range[0,20]+1)^11 (* _Harvey P. Dale_, May 11 2011 *)

%o (Magma) [(10*n+1)^11: n in [0..20]]; // _Vincenzo Librandi_, May 15 2011

%Y Cf. A008455 (n^11), A017281 (10n+1).

%K nonn,easy

%O 0,2

%A _N. J. A. Sloane_