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a(n) = (8*n + 1)^12.
1

%I #12 Sep 08 2022 08:44:41

%S 1,282429536481,582622237229761,59604644775390625,1667889514952984961,

%T 22563490300366186081,191581231380566414401,1176246293903439668001,

%U 5688009063105712890625,22902048046490258711521,79766443076872509863361

%N a(n) = (8*n + 1)^12.

%H Vincenzo Librandi, <a href="/A017088/b017088.txt">Table of n, a(n) for n = 0..10000</a>

%H <a href="/index/Rec#order_13">Index entries for linear recurrences with constant coefficients</a>, signature (13, -78, 286, -715, 1287, -1716, 1716, -1287, 715, -286, 78, -13, 1).

%o (Magma) [(8*n+1)^12: n in [0..20]]; // _Vincenzo Librandi_, Jul 11 2011

%K nonn,easy

%O 0,2

%A _N. J. A. Sloane_