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a(n) = (7*n + 4)^4.
1

%I #21 Sep 08 2022 08:44:41

%S 256,14641,104976,390625,1048576,2313441,4477456,7890481,12960000,

%T 20151121,29986576,43046721,59969536,81450625,108243216,141158161,

%U 181063936,228886641,285610000,352275361,429981696,519885601,623201296,741200625,875213056,1026625681

%N a(n) = (7*n + 4)^4.

%H Vincenzo Librandi, <a href="/A017032/b017032.txt">Table of n, a(n) for n = 0..10000</a>

%H <a href="/index/Rec#order_05">Index entries for linear recurrences with constant coefficients</a>, signature (5,-10,10,-5,1).

%F G.f.: -(81*x^4 + 9595*x^3 + 34331*x^2 + 13361*x + 256) / (x-1)^5. - _Colin Barker_, Oct 21 2015

%F a(n) = A000583(A017029(n)). - _Michel Marcus_, Oct 21 2015

%t (7*Range[0, 20] + 4)^4 (* _Harvey P. Dale_, Mar 03 2012 *)

%o (Magma) [(7*n+4)^4: n in [0..40] ]; // _Vincenzo Librandi_, Jul 16 2011

%o (PARI) Vec(-(81*x^4+9595*x^3+34331*x^2+13361*x+256)/(x-1)^5 + O(x^50)) \\ _Colin Barker_, Oct 21 2015

%Y Cf. A000583 (n^4), A017029 (7*n+4).

%K nonn,easy

%O 0,1

%A _N. J. A. Sloane_