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a(n) = (4n+1)^10.
1

%I #15 Jul 16 2017 20:49:52

%S 1,9765625,3486784401,137858491849,2015993900449,16679880978201,

%T 95367431640625,420707233300201,1531578985264449,4808584372417849,

%U 13422659310152401,34050628916015625,79792266297612001,174887470365513049,362033331456891249,713342911662882601

%N a(n) = (4n+1)^10.

%H T. D. Noe, <a href="/A016822/b016822.txt">Table of n, a(n) for n = 0..1000</a>

%H <a href="/index/Rec#order_11">Index entries for linear recurrences with constant coefficients</a>, signature (11, -55, 165, -330, 462, -462, 330, -165, 55, -11, 1).

%F a(n) = A008454(A016813(n)). - _Michel Marcus_, Jun 21 2016

%F G.f.: (1 + 9765614*x + 3379362581*x^2 + 100040972648*x^3 + 689712304370*x^4 + 1514068354580*x^5 + 1167881384066*x^6 + 306865115624*x^7 + 22833444557*x^8 + 281825710*x^9 + 59049*x^10)/(1 - x)^11. - _Ilya Gutkovskiy_, Jun 21 2016

%t Table[(4n+1)^10,{n,0,100}] (* _Mohammad K. Azarian_, Jun 20 2016 *)

%Y Cf. A008454, A016813.

%K nonn,easy

%O 0,2

%A _N. J. A. Sloane_.