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a(n) = (2*n)^11.
2

%I #24 Sep 08 2022 08:44:41

%S 0,2048,4194304,362797056,8589934592,100000000000,743008370688,

%T 4049565169664,17592186044416,64268410079232,204800000000000,

%U 584318301411328,1521681143169024,3670344486987776,8293509467471872,17714700000000000,36028797018963968,70188843638032384

%N a(n) = (2*n)^11.

%H Vincenzo Librandi, <a href="/A016751/b016751.txt">Table of n, a(n) for n = 0..10000</a>

%H <a href="/index/Rec#order_12">Index entries for linear recurrences with constant coefficients</a>, signature (12,-66,220,-495,792,-924,792,-495,220,-66,12,-1).

%F G.f.: 2048*x*(1 + 2036*x + 152637*x^2 + 2203488*x^3 + 9738114*x^4 + 15724248*x^5 + 9738114*x^6 + 2203488*x^7 + 152637*x^8 + 2036*x^9 + x^10)/(x-1)^12. - _R. J. Mathar_, Jul 07 2017

%F From _Amiram Eldar_, Oct 11 2020: (Start)

%F Sum_{n>=1} 1/a(n) = zeta(11)/2048.

%F Sum_{n>=1} (-1)^(n+1)/a(n) = 1023*zeta(11)/2097152. (End)

%p A016751:=n->(2*n)^11: seq(A016751(n), n=0..30); # _Wesley Ivan Hurt_, Sep 15 2018

%t Table[(2*n)^11, {n,0,30}] (* _G. C. Greubel_, Sep 15 2018 *)

%o (Magma) [(2*n)^11: n in [0..20]]; // _Vincenzo Librandi_, Sep 05 2011

%o (PARI) vector(30, n, n--; (2*n)^11) \\ _G. C. Greubel_, Sep 15 2018

%Y Cf. A016763.

%K nonn,easy

%O 0,2

%A _N. J. A. Sloane_