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%I #33 Dec 02 2022 17:17:32
%S 1,13,147,1625,17891,196833,2165227,23817625,261994131,2881935953,
%T 31701296507,348714263625,3835856903971,42194425951873,
%U 464138685486987,5105525540389625,56160780944351411,617768590387996593,6795454494268224667,74749999436950995625
%N Expansion of 1/((1-2*x)*(1-11*x)).
%H Vincenzo Librandi, <a href="/A016135/b016135.txt">Table of n, a(n) for n = 0..300</a>
%H <a href="/index/Rec#order_02">Index entries for linear recurrences with constant coefficients</a>, signature (13,-22).
%F a(n) = (11^(n+1) - 2^(n+1))/9. - _Zerinvary Lajos_, Jun 05 2009
%F a(n) = 13*a(n-1) - 22*a(n-2). - _Vincenzo Librandi_, Jun 02 2011
%t LinearRecurrence[{13,-22},{1,13},30] (* or *) CoefficientList[Series[ 1/((1-2x)*(1-11x)),{x,0,30}],x] (* _Harvey P. Dale_, Oct 15 2011 *)
%o (Sage) [(11^(n+1) - 2^(n+1))/9 for n in range(0,20)] # _Zerinvary Lajos_, Jun 05 2009
%o (PARI) a(n)=(11^n++-2^n)/9 \\ _Charles R Greathouse IV_, Mar 26 2012
%Y Cf. A139740.
%K nonn,easy
%O 0,2
%A _N. J. A. Sloane_
%E Incorrect comment removed by _Charles R Greathouse IV_, Mar 26 2012
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