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A015775
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Numbers n such that (phi(n) + 1) | sigma(n + 1), where phi is Euler's totient function A000010.
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5
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2, 4, 16, 25, 170, 256, 264, 1920, 9384, 26664, 65536, 263040, 437760, 1057800, 2038648320
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OFFSET
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1,1
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COMMENTS
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For 0 <= k <= 4, p = 2^(2^k) + 1 is a (Fermat) prime, so sigma(p) = p + 1 = 2*(2^(2^k-1) + 1) and phi(2^(2^k)) = 2^(2^k-1), so we have sigma(p) = 2*(phi(p-1) + 1) and n = p-1 = 2^(2^k) is in the sequence. For k = 5 this is no more the case. - M. F. Hasler, Dec 10 2018
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LINKS
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MAPLE
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with(numtheory): select(n->modp(sigma(n+1), phi(n)+1)=0, [$1..10000]); # Muniru A Asiru, Dec 10 2018
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MATHEMATICA
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Select[Range[10000], Mod[DivisorSigma[1, #+1], EulerPhi[#] +1] == 0 &] (* G. C. Greubel, Dec 10 2018 *)
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PROG
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CROSSREFS
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KEYWORD
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nonn,more
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AUTHOR
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EXTENSIONS
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Incorrect a(1) = 1 removed and a(12)-a(14) added by Sean A. Irvine, Dec 10 2018
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STATUS
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approved
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