

A014960


Numbers n such that n divides s(n), where s(1)=1, s(k)=s(k1)+k*24^(k1) (A014942).


7



1, 23, 529, 1081, 12167, 24863, 50807, 279841, 571849, 1168561, 2387929, 2870377
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OFFSET

1,2


COMMENTS

Initial terms are 23^n, 23^(n1)*47, 23^(n2)*47^2,...23*47^(n1),23^(n+1), etc. with sometime a little "noise" between terms (eg.: for a(12)=23*124799 between a(11)=23*47^3 and maybe a(13)=23^5). Maybe another sequence is interlaced, which would involve 23^n, 23^(n1)*124799, etc., in which case an infinity of products of powers of 23 and powers of another prime factor may occur in the sequence. Conjecture: Next term, a(13), very probably is 23^5. Conjecture: All numbers in the sequence are multiple of 23. Conjecture: All numbers in the sequence have at most two different prime factors.  Thomas Baruchel, Oct 10 2003


LINKS

Table of n, a(n) for n=1..12.


MATHEMATICA

s = 1; Do[ If[ Mod[ s, n ] == 0, Print[n]]; s = s + (n + 1)*24^n, {n, 1, 100000}]


CROSSREFS

Cf. A014942.
Sequence in context: A171328 A097778 A057193 * A207230 A207223 A207010
Adjacent sequences: A014957 A014958 A014959 * A014961 A014962 A014963


KEYWORD

nonn


AUTHOR

Olivier Gérard


EXTENSIONS

More terms from Robert G. Wilson v, Sep 13 2000
Four more terms from Thomas Baruchel, Oct 10 2003


STATUS

approved



