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%I #45 Jan 15 2022 00:31:49
%S 1,3,19,983,1140455,25739184407616,687786653376698575362597850,
%T 531547061991816754123214108000546228669815660470108834
%N Denominators of sign-alternating Egyptian fraction expansion of e - 2.
%C The greedy alternating Egyptian fraction for e-2 must begin with 1/1 as the (-1)^0 term. - _Greg Huber_, May 17 2018
%C a(n) >= a(n-1)^2 + a(n-1) for n >= 1, so the ratio log(a(n))/2^n is strictly increasing. But does it approach a limit? Conjecture: lim_{n->infinity} log(a(n))/2^n = 0.9748... - _Jon E. Schoenfield_, Jun 22 2018
%H Greg Huber, <a href="/A014015/b014015.txt">Table of n, a(n) for n = 0..8</a>
%H <a href="/index/Ed#Egypt">Index entries for sequences related to Egyptian fractions</a>
%K nonn
%O 0,2
%A _Simon Plouffe_
%E Initial 2 removed, offset corrected and Name clarified by _Greg Huber_, May 17 2018
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