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a(n) = 22^(4*n+1).
1

%I #19 Sep 08 2022 08:44:38

%S 22,5153632,1207269217792,282810057883082752,66249952919459433152512,

%T 15519448971100888972574851072,3635524038174209847159494312722432,

%U 851643319086537701956194499721106030592,199502557355935975909450298726667414302359552

%N a(n) = 22^(4*n+1).

%H Vincenzo Librandi, <a href="/A013816/b013816.txt">Table of n, a(n) for n = 0..100</a>

%H Tanya Khovanova, <a href="http://www.tanyakhovanova.com/RecursiveSequences/RecursiveSequences.html">Recursive Sequences</a>

%H <a href="/index/Rec#order_01">Index entries for linear recurrences with constant coefficients</a>, signature (234256).

%t Table[22^(4 n + 1), {n, 0, 10}] (* _Wesley Ivan Hurt_, Apr 11 2017 *)

%t NestList[234256#&,22,10] (* _Harvey P. Dale_, Apr 21 2022 *)

%o (Magma) [22^(4*n+1): n in [0..15]]; // _Vincenzo Librandi_, Jul 07 2011

%Y Subsequence of A009966.

%K nonn,easy

%O 0,1

%A _N. J. A. Sloane_