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 A013709 a(n) = 4^(2n+1). 14
 4, 64, 1024, 16384, 262144, 4194304, 67108864, 1073741824, 17179869184, 274877906944, 4398046511104, 70368744177664, 1125899906842624, 18014398509481984, 288230376151711744, 4611686018427387904 (list; graph; refs; listen; history; text; internal format)
 OFFSET 0,1 COMMENTS Also powers of 2 with singly even numbers (A016825) as exponents. - Alonso del Arte, Sep 03 2012 The partial sum of A000888(n) = Catalan(n)^2*(n + 1) resp. A267844(n) = Catalan(n)^2*(4n + 3) resp. A267987(n) = Catalan(n)^2*(4n + 4) divided by A013709(n) (this) a(n) = 2^(4n+2) absolutely converge to 1/Pi resp. 1 resp. 4/Pi. Thus this series is 1/Pi resp. 1 resp. 4/Pi. - Ralf Steiner, Jan 23 2016 LINKS Vincenzo Librandi, Table of n, a(n) for n = 0..200 Tanya Khovanova, Recursive Sequences Index entries for linear recurrences with constant coefficients, signature (16). FORMULA a(n) = 16*a(n - 1), n > 0; a(0) = 4. G.f.: 4/(1 - 16*x). [Philippe Deléham, Nov 23 2008] a(n) = 4^(2*n + 1) = 2^(4*n + 2). - Alonso del Arte, Sep 03 2012 a(n) = 4*A001025(n). - Michel Marcus, Jan 30 2016 MAPLE A013709:=n->4^(2*n+1): seq(A013709(n), n=0..20); # Wesley Ivan Hurt, Jan 30 2016 MATHEMATICA 2^(4 Range[0, 15] + 2) (* Alonso del Arte, Sep 03 2012 *) NestList[16#&, 4, 20] (* Harvey P. Dale, Jun 03 2013 *) PROG (MAGMA) [4^(2*n+1): n in [0..20]]; // Vincenzo Librandi, May 26 2011 (PARI) a(n)=4<<(4*n) \\ Charles R Greathouse IV, Apr 07 2012 CROSSREFS Cf. A000888, A001025, A013709, A016825, A267844, A267987. Sequence in context: A026301 A010042 A154021 * A139292 A152923 A085807 Adjacent sequences:  A013706 A013707 A013708 * A013710 A013711 A013712 KEYWORD nonn,easy AUTHOR STATUS approved

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Last modified April 22 08:25 EDT 2019. Contains 322329 sequences. (Running on oeis4.)