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A011943 Numbers n such that any group of n consecutive integers has integral standard deviation {viz. A011944(n)}. 15
1, 7, 97, 1351, 18817, 262087, 3650401, 50843527, 708158977, 9863382151, 137379191137, 1913445293767, 26650854921601, 371198523608647, 5170128475599457, 72010600134783751, 1002978273411373057 (list; graph; refs; listen; history; internal format)
OFFSET

1,2

COMMENTS

If k is in the sequence, then it has successor 7*k + 4*sqrt{3*(k^2 - 1)}. - Lekraj Beedassy (blekraj(AT)yahoo.com), Jun 28 2002

Chebyshev's polynomials T(n,x) evaluated at x=7.

a(n+1) give all (nontrivial) solutions of Pell equation a(n+1)^2 - 48*b(n+1)^2 = +1 with b(n+1)=A007655(n+2), n>=0.

Also numbers x of the form 3k+1 such that x^2 = 3n^2+1. Also solutions of x in x^2 - 3*y^2 = 1 in A001075 if x = 3k+1 k=1,2,... - Cino Hilliard (hillcino368(AT)gmail.com), Mar 05 2005

Equals sqrt(12*A011944(n)^2 + 1).

In addition to having integral standard deviation, these n consecutive integers also have integral mean. This question was posed by Jim Delany of Cal Poly in 1989. The solution appeared in the American Mathematical Monthly Vol. 97, No. 5, (May, 1990), pp. 432 as problem E3302. - Ronald S. Tiberio (chuck_tiberio(AT)wellesley.k12.ma.us), Jun 23 2008

Lebl and Lichtblau give the formula a(d) = ((7+4*sqrt(3))^d + (7-4*sqrt(3))^d)/2 in Theorem 1.2(iii), p.4. - Jonathan Vos Post (jvospost3(AT)gmail.com), Aug 05 2008

REFERENCES

E. K. Lloyd "The standard deviation of 1, 2, .., n, Pell's equation and rational triangles", preprint.

LINKS

Tanya Khovanova, Recursive Sequences

Jiri Lebl and Daniel Lichtblau, Uniqueness of certain polynomials constant on a hyperplane

Index entries for sequences related to Chebyshev polynomials.

Index entries for sequences related to linear recurrences with constant coefficients

FORMULA

a(m) = 14a(m-1) - a(m-2).

a(n) ~ (1/2)*(2 + sqrt(3))^(2*n) - Joe Keane (jgk(AT)jgk.org), May 15 2002

a(n) = T(n, 7) = (S(n, 14)-S(n-2, 14))/2 = T(2*n, 2) with S(n, x) := U(n, x/2) and T(n, x), resp. U(n, x), are Chebyshev's polynomials of the first, resp. second, kind. See A053120 and A049310. S(-2, x) := -1, S(-1, x) := 0, S(n, 14)=A007655(n+2).

a(n) = ((7+4*sqrt(3))^n + (7-4*sqrt(3))^n)/2.

a(n) = sqrt(48*A007655(n+1)^2 + 1).

G.f.: (1-7*x)/(1-14*x+x^2).

a(n) = Cosh[2n*ArcSinh[Sqrt[3]]] - Herbert Kociemba (kociemba(AT)t-online.de), Apr 24 2008

PROG

(PARI) a(n)=if(n<0, 0, subst(poltchebi(n), x, 7))

(PARI) g(n) = forstep(x=1, n, 3, y=(x^2-1)/3; if(issquare(y), print1(x", "))) (Hilliard)

CROSSREFS

a(n)=A001075(2n)

Row 2 of array A188644

Cf. A007654, A011944.

Sequence in context: A093172 A074110 A155644 * A188441 A178808 A083083

Adjacent sequences:  A011940 A011941 A011942 * A011944 A011945 A011946

KEYWORD

nonn,easy

AUTHOR

E. K. Lloyd

EXTENSIONS

Better description from Lekraj Beedassy (blekraj(AT)yahoo.com), Jun 27 2002

Chebyshev comments from W. Lang (wolfdieter.lang(AT)physik.uni-karlsruhe.de), Nov 08 2002

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Last modified February 15 14:55 EST 2012. Contains 205822 sequences.