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A011769
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a(0) = 1, a(n+1) = 3 * a(n) - F(n)*(F(n) + 1), where F(n) = A000045(n) is n-th Fibonacci number.
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1
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1, 3, 7, 19, 51, 141, 393, 1107, 3139, 8955, 25675, 73945, 213825, 620595, 1807263, 5279283, 15465139, 45420261, 133708777, 394446691, 1165855131, 3451793403, 10235554347, 30392965809, 90357645121, 268922897571, 801139867063, 2388683219347, 7127469430899
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OFFSET
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0,2
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REFERENCES
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L. Euler, (E326) Observationes analyticae, reprinted in: Opera Omnia. Teubner, Leipzig, 1911, Series (1), Vol. 15, p. 59.
R. L. Graham, D. E. Knuth and O. Patashnik, Concrete Mathematics. Addison-Wesley, Reading, MA, 1990, p. 575.
P. Henrici, Applied and Computational Complex Analysis. Wiley, NY, 3 vols., 1974-1986. (Vol. 1, p. 42.)
J. Riordan, Combinatorial Identities, Wiley, 1968, p. 74.
See also the references mentioned under A002426.
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LINKS
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FORMULA
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a(n) = +6*a(n-1) -8*a(n-2) -8*a(n-3) +14*a(n-4) +4*a(n-5) -3*a(n-6). [R. J. Mathar, Sep 04 2010]
G.f.: (1-3*x-3*x^2+9*x^3+3*x^4-3*x^5) / ( (3*x-1)*(1+x)*(x^2+x-1)*(x^2-3*x+1) ). - Sergei N. Gladkovskii, Dec 16 2011
a(n+1) = (1/10) * (3^n + 2*Lucas(2n) + Lucas(n) + (-1)^n ). - Ralf Stephan, Aug 10 2013
a(k) = 3^(k+1)*x^k/10 + (-1)^(k+1)*x^k/10 + p^(k+1)*x^k/5 + (-q)^(k+1)*x^k/5 + p^(2*k+2)*x^k/5 + q^(2*k+2)*x^k/5 ; p=(sqrt(5)+1)/2 , q=(sqrt(5)-1)/2 . - Sergei N. Gladkovskii, Dec 17 2011
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MAPLE
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A011769 := proc(n) if n = 0 then 1; else 3*procname(n-1)-combinat[fibonacci](n-1)*(1+combinat[fibonacci](n-1)) ; end if; end proc:
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MATHEMATICA
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nxt[{n_, a_}]:=Module[{fib=Fibonacci[n]}, {n+1, 3a-fib(fib+1)}]; Transpose[ [ nxt, {0, 1}, 30]][[2]] (* or *) LinearRecurrence[{6, -8, -8, 14, 4, -3}, {1, 3, 7, 19, 51, 141}, 30] (* Harvey P. Dale, Jun 05 2015 *)
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PROG
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(Haskell)
a011769 n = a011769_list !! n
a011769_list = 1 : zipWith (-) (map (* 3) a011769_list) a059727_list
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CROSSREFS
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KEYWORD
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nonn,easy
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AUTHOR
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EXTENSIONS
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STATUS
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approved
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