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a(n) = floor(n/2)^floor(n/3).
0

%I #12 Apr 22 2021 14:48:36

%S 1,1,2,2,9,9,16,64,125,125,1296,1296,2401,16807,32768,32768,531441,

%T 531441,1000000,10000000,19487171,19487171,429981696,429981696,

%U 815730721,10604499373,20661046784,20661046784

%N a(n) = floor(n/2)^floor(n/3).

%p [ seq(floor(n/2)^floor(n/3), n=2..100) ];

%t Table[Floor[n/2]^Floor[n/3],{n,2,30}] (* _Harvey P. Dale_, Dec 10 2016 *)

%Y Cf. A002264, A004526.

%K nonn

%O 2,3

%A _N. J. A. Sloane_, _Simon Plouffe_